Chemistry-Precipitation Essay

My apart(p) chemical is atomic number 11 iodide. This was determined by testing the chemical with cations such as silver treat, atomic number 27 (II) nitrate, and fuzz nitrate. It was also tried with anions sodium iodide, sodium carbonate, sodium oxalate, and sodium phosphate. It was tested to see if the product will bring back a precipitate or cheering state (cloudiness, power, or crystals) and any color changes that are very mistakable to the products/changes when entirely the known cations and anions were tested for changes.First of all, sodium iodide is an anion, it was determined that the unknown quantity chemical was an anion because it did not controvert with any of the anions. Since the unknown did not react with the anions, it did not produce a solid or precipitate. This is chemically straight because the new products will both contain NO3, or nitrate, and NO3 is aqueous with all cations.When the unknown was tested with silver nitrate a solid was produced, prec isely also the color was a light yellow that is quite give care to the description of the product of sodium iodide added to silver nitrate (a dull al one light yellow). This color was not exactly similar to the colors organize from other combinations as they were some yellow for the formula 2AgNO3(aq)+NaCO3(aq) AgCO3(s)+2NaNO3(aq) , white for 2AgNO3(aq)+NaC2O4(aq) AgC2O4(s)+2NaNO3(aq) , and chickenhearted for 3AgNO3(aq)+Na3PO4(aq) Ag3PO4(s)+3NaNO3(aq). A solid was organize in both situations due to a cloudy substance that formed with the silver nitrate + sodium iodide and the unknown + silver nitrate. It makes sense that a solid was formed becauseAgNO3(aq)+NaI(aq) AgI(s)+NaNO3(aq)On the stick out of the periodic delay it states that if the anion I- is part of the compound then cations like Ag+ and Pb2+ will form a solid with it. Since it is AgI, a solid is understandably formed.When the unknown was tested with cobalt (II) nitrate a solid was not produced and there was no col or change it was the same light sound as originally, similar to the description of the product of sodium iodide added to cobalt (II) nitrate which was same light pink as the original color of the mixture. A solid was not formed in both situations becauseCo(NO3)2(aq)+2NaI(aq) CoI2(aq)+2NaNO3(aq)According to the guts of the periodic table it states that if the anion iodine is part of the compound then cations like Ag+, Pb2+, Hg22+, and Cu+ will form a solid with it, scarcely iodine with all other cations form an aqueous solution. Therefore, since cobalt is not listed as one of the cations that iodine forms a solid with, no solid would be formed which is exactly what happened when sodium iodide was added to cobalt (II) nitrate and no other combination with cobalt (II) nitrate. Since sodium iodide in combination with cobalt (II) nitrate was the only one involving cobalt (II) nitrate that did not become a reaction it proves that the unknown is one of the two. But, since it has been p roven that unknown is an anion, sodium iodide is our only option.When the unknown was tested with shit (II) nitrate a solid was produced, but also the color was a dark orange-yellow that was not as well cloudy. This description is basically the same as the description of the product of sodium iodide added to squealer (II) nitrate which was dark yellow/range tone, copper color, moderately cloudy. A solid was formed in both situations because it was slightly cloudy in both situations.Cu(NO3)2 (aq)+2NaI(aq) CuI2(s)+2NaNO3(aq)According to the back of the periodic table it states that if the anion iodine is part of the compound then cations like Ag+, Pb2+, Hg22+, and Cu+ will form a solid with it. Therefore, since copper is listed as one of the cations that iodine forms a solid with, a solid would be formed which is exactly what happened when sodium iodide was added to copper (II) nitrate. Since sodium iodide in combination with copper (II) nitrate was the only combination to form a dark yellow/orange color of all 4 anions in combination with the cation copper (II) nitrate sodium iodide seems the only option for the unknown. It is also not probable that the unknown is copper (II) nitrate because if there is a precipitate and a color change, it would not be the same color because different formulas yield different reactions like the colors formed. They are all unique.